Down arrow? Probability question

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Office_Shredder
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A question on my probability problem set reads: If the sequence of events An is non-decreasing (i.e. An is a superset of An+1 for all n), prove the following

P[A_n] \downarrow P[\bigcap_{i=0}^\infty A_i]

I just need to know what the heck the down arrow means
 
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I think it means that the probabilities on the left are a non-increasing sequence converging to the number on the right (that's what you have to prove).
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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