Drawing a Frequency-Magnitude (Bode) Plot: Thomas's Questions

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To draw a frequency-magnitude (Bode) plot for the circuit in question, the user needs to determine the appropriate RC values. The circuit consists of a voltage divider with two impedances: a 100nF capacitor with a 20K resistor and another with a 10K resistor. While the user initially considered using a single RC value, it was clarified that the circuit can be simplified into two filter responses if the RC values differ significantly. However, in this case, the component values are too close for such simplification. Ultimately, the transfer function derived from the circuit will be essential for accurately plotting the Bode plot.
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I need to draw a frequency- magnitude (bode) plot of this circuit:

rccalc.png



Firstly I need to find the RC but I don't have a clue.

It's meant to be 1ms, and I guess that's from 10k * 100nF

BUT why is the 20K not involved?

Thanks
Thomas
 
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Looks to me like you've got a voltage divider comprising two impedances. One is the serial combination of a 100nF capacitor and a 20K resistor, and the other a 100nF capacitor and 10K resistor. You should be able to derive the transfer function on that basis.
 
I can easily derive the transfer function... but how do I find the RC value
 
thomas49th said:
I can easily derive the transfer function... but how do I find the RC value

Well, what do you mean by the "RC value"? The circuit is a combination of two filters.
 
in the transfer function there will be some jwRC. What is the value of RC? What resistors and caps contribute to the RC?
 
Hang on a sec. I've had a brainwave. I define the RC. I set R = 10K and C = 100nF. I've got myself confused...

Thanks for the help!
 
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thomas49th said:
Hang on a sec. I've had a brainwave. I define the RC. I set R = 10K and C = 100nF. I've got myself confused...

Thanks for the help!

Er, no.

You may be able to simplify that circuit into two RC responses, one HPF and one LPF, if the two RC values are far enough apart. That may be what you are referring to here.

Otherwise, you use the transfer function that you derived to draw the Bode plot...
 
berkeman said:
Er, no.

You may be able to simplify that circuit into two RC responses, one HPF and one LPF, if the two RC values are far enough apart. That may be what you are referring to here.

Otherwise, you use the transfer function that you derived to draw the Bode plot...

EDIT -- in the case of this circuit, the component values are too close together to use the trick of separating the LPF and HPF behaviors...
 
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