Drive line inertia and torsional effects exam question

AI Thread Summary
The discussion focuses on calculating inertial forces in gears and the relationships between torque and angular acceleration for connected shafts. It presents equations for torque and angular relationships, leading to a system of seven equations with seven unknowns. The approach suggested involves selecting an arbitrary rotation rate for one shaft, calculating the rotational kinetic energy (KE) for each shaft, and determining the effective moment of inertia for shafts B and C based on these KE values. An example calculation illustrates how to derive the effective moment of inertia for shaft B. The overall goal is to find the total effective moment of inertia for the system by summing the individual moments of inertia.
Alistair McCheyne
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Hi can anyone help me with this question on inertial forces in gears?
Cheers
Ali :)
 

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For every shaft i, you get:
\sum T_i = I_i \alpha_i
And for every gear i connected to gear j, you get:
\frac{T_{i\ out}}{T_{j\ in}} = \frac{N_i}{N_j}
\frac{\alpha_i}{\alpha_j} = \frac{N_j}{N_i}

This gives you 7 equations with 7 unknowns (T_{A\ out}, T_{B\ in}, T_{B\ out}, T_{C\ in}, \alpha_A, \alpha_B, \alpha_C).
 
i would be tempted to apportion an effective moment of inertia to shafts B & C (this takes into account the relative rotation rates)

Select an arbitrary rotation rate for shaft A (say 10 rad/sec)
Calculate the rotational KE of each shaft at this rate
The effective moment of inertia of shafts B and C you calculate by comparing the KE values to that of shaft A
For example :
The KE of shaft A at 10 rad / sec = 75 joules
The KE of shaft B at 5 rad / sec = 0.625 joules, so its effective moment of inertia = 1.5 * ( 0.625 / 75 ) = 0.0125 kg . m^2
Repeat for shaft C then add A, B and C for total effective moment of inertia of the system
 
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