Dropping the Ammunition Box: Physics Problem Explained

[homevolend]

Homework Statement

A plane flying 125 m/s horizontally drops an amunition box. The box falls for 18.6 s before touching down on the ground.

a) what height was dropped for the box.
b)what is verticle velocity when it hits ground.
c)how fast is traveling horizontally when hit ground.
d)how far did food fall during 5th second from being released.

Homework Equations

d=v1(t) + 1/2(a)(t²)

The Attempt at a Solution

a

t=18.6s
v1=125m/s

d=125(18.6) + .5(9.81)(18.6²)
d=2325 + 91.233²
d=2325+3393.9
height=5718.9

b


v₂²=v₁² + a(t)
v₂²=5718.9 + 2(9.81)(5718.9)
v₂=343.4 m/s


c

not sure how to do'


d

d=v1(t) + 1/2(a)(t²)
d=125(5) + .5(9.81)(5²)
d=747.6 M



Now I down know how to do c and not sure if I answered these questions correctly, just need some confirmation if I used the right math and forumulas because for a 5718 seems like an accurate distance but b doesn't seem like a good v₂..hows my answers look?

Thanks.

 

[americanforest]

In the vertical direction there is no initial velocity. It is just dropped, not thrown down (or up). There is only the constant acceleration due to gravity; that is all you need to take into account. The velocity in the horizontal direction, on the other hand, is just constant since there are no force components in that direction.

 

[homevolend]

Ok, I under stand you. So I did my questions wrong. For a and b ans d my v1 is zero. So I just use that then for my equation, but is my equations all the right ones to use. so only for c I would use the 125 m/s.