Dynamics Homework: Find Velocity/Acceleration & Time of Ball Hitting Ground

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The position of a ball kicked upwards is given by the equation y(t) = -4.9t^2 + 20t + 0.50 m. To find the vertical component of velocity and acceleration, the first and second derivatives of the position function are taken, resulting in velocity v(t) = -9.8t + 20 m/s and constant acceleration a = -9.8 m/s². To determine the time when the ball hits the ground, set the position equation y(t) equal to zero and solve for t. The discussion confirms the use of derivatives for finding velocity and acceleration, and emphasizes solving the equation for time at which y equals the ground level. This approach effectively addresses the dynamics of the ball's motion.
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Homework Statement


he position of a ball as its kicked upwards is measured as
y(t) =(-4.9 t^2 + 20t + 0.50)m,
where t is measured in seconds. Find the vertical component of velocity and acceleration of the ball as a function of time. If the ground is located at yg = 0, find the time at which the ball hits the ground.



Homework Equations



Cant I take the first and second derivative to find velocity and acc.? then i don't know how to solve for time

The Attempt at a Solution


would velocity= -9.8t + 20
acc.=-9.8??
 
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ihavaquestion said:
Cant I take the first and second derivative to find velocity and acc.?

Yes

ihavaquestion said:

The Attempt at a Solution


would velocity= -9.8t + 20
acc.=-9.8??

Yes and yes.

ihavaquestion said:
then i don't know how to solve for time

Using the expression for y(t), find the t at which y = yg.
 
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