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Dynamics problem of two bars

  1. Apr 6, 2014 #1
    Hello!, Im trying to solve this problem of the book beer vector mechanics for engineers statics and dynamics, I`ll be very glad if you can help me with this
    http://i.imgur.com/pFkUfuv.png (Image of the problem)
    Each of the two identical slender bars shown has a length L. Knowing that the system is released from rest when the bars are horizontal, calculate the equations for angular velocity(ω) of rod AB and velocity of point D for values of θ from 0 to 90 degrees.

    Here are some formulas that might help:
    I= 1/12 mL^2
    Principle of conservation of energy T1 + V1 = T2+V2
    V=mgh
    T= (1/2)*Iω^2
    V= ωxr

    First I tried to solve as a mechanism of three bars but it didn´t work and I´m trying to solve it with moments of Inertia I= 1/12 mL^2 and kinematics but the problem doesn´t say the mass of the rods, I also tried to solve for the equations of the two positions (when the rods are horizontal and when the angle is 90) but I can not get to anywhere
    Thanks for taking your time to read this.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
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