A 50.0 kg crate is dragged at a constant velocity of 1.5 m/s for a distance of 8.0 m. If the force of friction on the crate is 225 N, how much work was done by the person to drag the crate over the 8.0 m distance if the rope used to drag the crate was directed at 20degrees angle above the horizontal?(adsbygoogle = window.adsbygoogle || []).push({});

my work:

mass 50kg

distance 8m

angle 20 degrees

Force of Friction 225N

since we have a constant velocity Fnet = 0

Fnet = T - Ff

Solve for T

0 = T - 225N

T = 225N

therefore T x distance moved by the rope x cosx = work done

so I got 225N x 8m x cos20 = 1690 J

However the answer sheet says it's 1800 J............

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# Homework Help: Dynamics Question

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