E-field inside a non-conducting hollow pear.

  • Thread starter Thread starter Aesteus
  • Start date Start date
  • Tags Tags
    E-field
Click For Summary
SUMMARY

The discussion focuses on calculating the electric field inside a hollow non-conducting pear with a specific surface charge distribution, σ(r,θ), ranging from 0 C/m² at the top to 600 C/m² at the bottom. The solution involves applying Gauss's Law, which confirms that the electric field inside the pear is zero due to the absence of enclosed charge. The symmetry of the charge distribution allows for simplification in the analysis, particularly along the z-axis.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric field concepts and superposition principle
  • Knowledge of surface charge distributions and their effects
  • Basic grasp of Laplace's equation and its applications
NEXT STEPS
  • Study the applications of Gauss's Law in various geometries
  • Explore the implications of symmetry in electrostatics
  • Learn about electric field calculations in non-conducting materials
  • Investigate Laplace's equation and its role in electrostatic problems
USEFUL FOR

Students and professionals in physics, particularly those focusing on electrostatics, as well as educators looking for examples of electric field calculations in non-conducting materials.

Aesteus
Messages
17
Reaction score
0

Homework Statement



Find the electric field inside a hollow non-conducting pear with a surface charge-distribution (axially symmetric too) of σ(r,θ). The charge density σ is zero at the top of the pear, and 600 C/m^2 at the bottom.

Homework Equations



I'm not sure how to approach the problem ... maybe some application of Laplace's equation.

The Attempt at a Solution



The electric field at any point inside the pear will be the superposition of x,y, and z fields. I assume that we can use symmetry about the z-axis to our advantage.
 
Physics news on Phys.org
Nevermind, it's just a simple application of gauss' law on the inside of the object yielding E=0 because there is no enclosed charge. (And E-z is non-zero I believe.)
 

Similar threads

Replies
23
Views
5K
  • · Replies 36 ·
2
Replies
36
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
1K
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
347
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
2K
Replies
5
Views
1K