E = hf what sort of Energy is this?

AI Thread Summary
The discussion centers on the relationship between energy expressed in the equation E = hf and its relevance to the equation E² = (mc²)² + (pc)². It clarifies that the energy (E) in E = hf pertains specifically to photons, which are massless particles. Participants confirm that this energy can indeed be related to the broader energy equation for particles, including those with mass. The conversation emphasizes the distinction between photon energy and the energy of massive particles. Understanding these relationships is crucial for grasping concepts in quantum mechanics and relativity.
WWCY
Messages
476
Reaction score
14

Homework Statement


Is this E - say of an electron - the very E in E2 = (mc2)2 + (pc)2?

If it isn't, what sort of Energy is this?

Help is greatly appreciated!

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
This is the E of a photon, a massless particle. So yes:
WWCY said:
the very E in E2 = (mc2)2 + (pc)2?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top