E(X^r) from Weibull Distribution is equal to Gamma Fn

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Homework Statement



I have f(x) = BxB-1e-x^B

I need to show that E(Xr) = Ƭ(Gamma)(R/B + 1)

Homework Equations


I know that E(Xr) = f(x)


The Attempt at a Solution



Attempt at part of solution

I started by saying let u = xB so du = BxB-1dx

Can I say then that if u = xB, then Xr = ur/B

That’s my first question. If I am on the right lines I will integrate. I think I have asked this before, but it got removed as I hadn’t followed the guidelines. Hoping that is set out properly. I am integrating by substitution. Assuming this is possible and I don’t HAVE to integrate by parts.Many thanks
[/B]
 
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Nick Jarvis said:

Homework Statement



I have f(x) = BxB-1e-x^B

I need to show that E(Xr) = Ƭ(Gamma)(R/B + 1)

Homework Equations


I know that E(Xr) = f(x)


The Attempt at a Solution



Attempt at part of solution

I started by saying let u = xB so du = BxB-1dx

Can I say then that if u = xB, then Xr = ur/B

That’s my first question. If I am on the right lines I will integrate. I think I have asked this before, but it got removed as I hadn’t followed the guidelines. Hoping that is set out properly. I am integrating by substitution. Assuming this is possible and I don’t HAVE to integrate by parts.Many thanks[/B]
(1) Please refrain from putting all of your message in a bold font; it looks like you are yelling at us.
(2) When writing you must distinguish clearly between ##u = xB## and ##u = x^B##.
(3) And, yes, of course, if ##u = x^B## then ##x^r = u^{B/r}## for any ##x > 0##. How could it be otherwise?
(4) I hope you were are being asked to prove that
$$ E X^r = \Gamma \left( \frac{r}{B}+1 \right) \; ?$$
rather than
$$ E X^r = \Gamma \left( \frac{r}{B+1} \right) \: ?$$
because the second one of these is false.
 
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Thanks. I copied and pasted from Word and assume the bold was inherited from the the 3 titles in the template. Apologies for that.

I cannot work out to insert nice equations like the two that you have inserted above. And yes, I need to prove that:

E(Xr)=Γ((r/B)+1) - your first equation

When I ask 'Can I say then that if u = xB, then Xr = ur/B' I meant is this the correct way of starting to solve it? Or am I on a hiding to nothing?

Many thanks
 
Nick Jarvis said:
Thanks. I copied and pasted from Word and assume the bold was inherited from the the 3 titles in the template. Apologies for that.

I cannot work out to insert nice equations like the two that you have inserted above. And yes, I need to prove that:

E(Xr)=Γ((r/B)+1) - your first equation

When I ask 'Can I say then that if u = xB, then Xr = ur/B' I meant is this the correct way of starting to solve it? Or am I on a hiding to nothing?

Many thanks

You can get rid of the bold font, just by making sure your input occurs after the "[/B]" delimiter. In this forum, "[B ]" turns on bold and "[/B ]" turns it off. (Note: I inserted extra space after the "B" and before the "]" to prevent the processor from actually switching to bold, but there should be no space between them.)

To insert "nice" equations, just use LaTeX; a stripped-down version of it comes loaded into this Forum. For an in-line equation, use # # d = a + b c^2 \int_0^1 x^3 dx # # (with no space between the two #'s at the start and at the end); that produces ##d = a + b c^2 \int_0^1 x^3 \, dx##. For a "dsplayed" equation (on its own, separate line) use two $ signs (with no space between them) at the start and at the end. That gives
$$d = a + b c^2 \int_0^1 x^3 \, dx$$
If you search in this Forum for a "LaTeX tutorial", I am sure you will find one. To see the actual typed commands for a LaTeX expression, just right-click on the expression or equation and ask for a display math as tex.

As to your question: the fall-back position is to always try it yourself, to see what you get. If it works, you are done; if it fails, you need to try something else. But, try it first.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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