Calculating Impulse of a Collision: A Simple Guide

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To calculate the impulse of a collision, the equation used is Impulse = Force x Time. Given an average force of 509.79 N and a collision time of 35.1 milliseconds, the impulse can be calculated directly in Newton-seconds. There is confusion regarding the desired unit of Joules-seconds, as impulse is typically expressed in Newton-seconds, which is equivalent to momentum. The discussion suggests that the request for Joules-seconds may be a typo. Ultimately, the correct calculation should yield the impulse in Newton-seconds.
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I was to calculate the impulse of a collision. I was given the Average force in Newton, and the collison time in seconds. I need the answer to be in Joules - Seconds and not in Newton - Seconds. I used the equation Impulse = Force x Time. I am have a tremendous brain fart. Can you help?
 
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I don't think you want your answer to be in Joule-seconds, since that's not the unit of momentum...

What's the context?
 
A collision occurs w/ a time of impact is 35.1 milliseconds and the average force is 509.79 N. What is the impulse (in Joules-Seconds)?
 
I would just go with F*t and ignore that part. It may just be a typo
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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