Sir, The eccentricity of earths orbit is 0.0167. What is the ratio of its maximum speed to its minimum speed in its orbit? I solved it in the following way: Let its maximum and minimum speed be v1 and v2 respectively. Let a and b be the semi length of the major and minor axis respectively. Let e be its eccentricity. v is inversely proportional to a and b. I took this assumption because at points closest to the centre of the elliptical path the velocity is maximum. Hence, v1/v2 = a/b Now for an ellipse, (1 – e^2) = (b/a)^2 By solving I get, a/b = 1.00014 Therefore, v1/v2 = 1.00014 But the book answer is 1.033. Is there any mistake?