- #1
Delzac
- 389
- 0
Homework Statement
As given in the picture.
The Attempt at a Solution
So this is what i have done.
I calculated:
[tex] \frac{d\phi}{dt} = B \pi b^2 *\frac{\omega}{2\pi} = e.m.f.[/tex]
[tex] R = \frac{\rho a}{at} [/tex]
Thus, [tex] I = emf/R = \frac{ar \omega t}{\rho} [/tex]
Sub in I into F = BIL taking L as a.
But i have a feeling that this is wrong, cause the working is too simple.
Any help will be greatly appreciated.