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gracy
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http://postimg.org/image/p7sz481cv/
I now know what is effective distance
Suppose you have two charges embedded in a dielectric medium with constant k (so instead of empty space there's a "sea" of dielectric media around them). They are separated by a distance d in the medium, so that Coulomb's law would be:
##F##=##\frac{1}{k 4 \pi ε_o}####\frac{q_1 q_2}{d^2}##
Now we want to know what the effective distance would be in empty space to produce the same force. So:
##\frac{1}{k~4 \pi ε_o}## ##\frac{q_1 q_2}{d^2}## = ##\frac{1}{4 \pi ε_o} \frac{q_1 q_2}{d_{eff}^2}##
which reduces to
##k~d^2## = ##d_{eff}^2##
If we look at the image I have given link of how the net distance between the charges has been calculated there?
I now know what is effective distance
Suppose you have two charges embedded in a dielectric medium with constant k (so instead of empty space there's a "sea" of dielectric media around them). They are separated by a distance d in the medium, so that Coulomb's law would be:
##F##=##\frac{1}{k 4 \pi ε_o}####\frac{q_1 q_2}{d^2}##
Now we want to know what the effective distance would be in empty space to produce the same force. So:
##\frac{1}{k~4 \pi ε_o}## ##\frac{q_1 q_2}{d^2}## = ##\frac{1}{4 \pi ε_o} \frac{q_1 q_2}{d_{eff}^2}##
which reduces to
##k~d^2## = ##d_{eff}^2##
If we look at the image I have given link of how the net distance between the charges has been calculated there?