Efficient Methods for Solving Integrals with Trigonometric Substitution

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1. integral(e^(2x)/\sqrt{}(e^2^x+1))dx and integral(e^(x)/\sqrt{}(e^2^x+1))dx







3. I tried solvign by letting u=e^x and used trig substitution for \sqrt{}u^2+1 where x=tan(theta), d(theta)=sec^2(theta), \sqrt{}u^2+1=sec(theta) but got stuck
 
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\int\frac{e^{2x}}{\sqrt(e^{2x}+1)}dx letting

t^{2}=e^{2x}+1=>2tdt=2e^{2x}dx=>tdt=e^{2x}dx,
I think you can go from here, right? Similarly try the other, and show a little more work please!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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