# Einstein index notation

## Main Question or Discussion Point

Hello
I am doing some exercises in continuum mechanics and it is a little bit confusing. I am given the following equations $A_{ij}= \delta_{ij} +au_{i}v_{j}$ and $(A_{ij})^{-1} = \delta_{ij} - \frac{au_{i}v_{j}}{1-au_{k}v_{k}}$. If I want to take the product to verify that they give the identity matrix (its components maybe is more accurate), should I change in one of the expressions the index letters and proceed(change the free indices I mean)? Is this the correct approach $(\delta_{ij} +au_{i}v_{j})(\delta_{mn} - \frac{au_{m}v_{n}}{1-au_{k}v_{k}})$ and do the calculations? Does this term make sense $\delta_{ij}\delta_{mn}$?

Thanks lot

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BvU
Homework Helper
2019 Award
Hello $\Theta$, You don't want four indices, but three: one to sum over and the other two are the indices of the product matrix.

Consider matrices A, B and C: what is the expression for $C_{ij}$ in terms of $A_{..}$ and $B_{..}$ ?

PS do you mean $A^{-1}_{ij}$ as in $(A^{-1})_{ij}$ ?

Hello $\Theta$, You don't want four indices, but three: one to sum over and the other two are the indices of the product matrix.

Consider matrices A, B and C: what is the expression for $C_{ij}$ in terms of $A_{..}$ and $B_{..}$ ?

PS do you mean $A^{-1}_{ij}$ as in $(A^{-1})_{ij}$ ?
I believe it is $C_{ij}=A_{ik}B_{kj}$ ? Yes you are correct it is $A_{ij}^{-1}$ my mistake. So if I keep three free indices I have something like : $C_{ij}=(\delta_{im} +au_{i}v_{m})(\delta_{mj} - \frac{au_{m}v_{j}}{1-au_{k}v_{k}})= \delta_{im}\delta_{mj}- \delta_{im}\frac{au_{m}v_{j}}{1-au_{k}v_{k}} +\delta_{mj}au_{i}v_{m} -au_{i}v_{m}\frac{au_{m}v_{j}}{1-au_{k}v_{k}}$ ?

Einstein notation.... Sorry mate it's all about the lathes, spanners and Sir Issac around here.

PeroK
Homework Helper
Gold Member
I believe it is $C_{ij}=A_{ik}B_{kj}$ ? Yes you are correct it is $A_{ij}^{-1}$ my mistake. So if I keep three free indices I have something like : $C_{ij}=(\delta_{im} +au_{i}v_{m})(\delta_{mj} - \frac{au_{m}v_{j}}{1-au_{k}v_{k}})= \delta_{im}\delta_{mj}- \delta_{im}\frac{au_{m}v_{j}}{1-au_{k}v_{k}} +\delta_{mj}au_{i}v_{m} -au_{i}v_{m}\frac{au_{m}v_{j}}{1-au_{k}v_{k}}$ ?
Yes, that's the idea.

Yes, that's the idea.
I think I completed it. thank you.

• BvU
Einstein notation.... Sorry mate it's all about the lathes, spanners and Sir Issac around here.
I think fluids is a specialty of Mech,Eng.? and you need tensors.