EL Equations for the modified electromagnetic field Lagrangian

Irrational
Messages
46
Reaction score
0
Hi,

I'm trying to work through something and it should be quite simple but somehow I've gotten a bit confused.

I've worked through the Euler Lagrange equations for the lagrangian:

<br /> \begin{align*}<br /> \mathcal{L}_{0} &amp;= -\frac{1}{4}(\partial_{\mu}A_{\nu})(\partial^{\mu}A^{\nu}) \\<br /> &amp;= \frac{1}{4}F_{\mu\nu}F^{\mu\nu}<br /> \end{align*}<br />

getting:

\Box A_{\nu} - \partial^{\nu}\partial_{\mu}A^{\mu} = 0

I'm ok with this.

Then considering the modified lagrangian:

\mathcal{L}_{\xi} = \mathcal{L}_{0} + \frac{\lambda}{2}(\partial_{\sigma}A^{\sigma})^2

I'm trying to work out the EL equation components and as part of one of these calculations, I've to calculate:

<br /> \begin{align*}<br /> \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} \left[ \frac{\lambda}{2} (\partial_{\sigma}A^{\sigma})^2 \right] <br /> <br /> &amp;= \frac{\lambda}{2} \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} \left[ ( \partial_{\sigma}A^{\sigma} ) ( \partial_{\rho}A^{\rho} ) \right] \\<br /> <br /> &amp;= \frac{\lambda}{2} \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} \left[ ( \partial_{\sigma}A_{\alpha} \eta^{\sigma \alpha} ) ( \partial_{\rho}A_{\beta} \eta^{\rho \beta} ) \right] \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\rho \beta} \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} \left[ ( \partial_{\sigma}A_{\alpha} ) ( \partial_{\rho}A_{\beta} ) \right] \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\rho \beta} \left[ ( \partial_{\sigma}A_{\alpha} ) \left( \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} ( \partial_{\rho}A_{\beta} ) \right) + \left( \frac{\partial}{\partial(\partial_{\mu}A_{\nu})} ( \partial_{\sigma}A_{\alpha} ) \right) ( \partial_{\rho}A_{\beta} ) \right] \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\rho \beta} \left[ ( \partial_{\sigma}A_{\alpha} ) \delta^{\mu}_{\rho} \delta^{\nu}_{\beta} + \delta^{\mu}_{\sigma} \delta^{\nu}_{\alpha} ( \partial_{\rho}A_{\beta} ) \right] \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\rho \beta} ( \partial_{\sigma}A_{\alpha} ) \delta^{\mu}_{\rho} \delta^{\nu}_{\beta}<br /> + <br /> \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\rho \beta} \delta^{\mu}_{\sigma} \delta^{\nu}_{\alpha} ( \partial_{\rho}A_{\beta} ) \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\sigma \alpha} \eta^{\mu \nu} ( \partial_{\sigma}A_{\alpha} )<br /> + <br /> \frac{\lambda}{2} \eta^{\mu \nu} \eta^{\rho \beta} ( \partial_{\rho}A_{\beta} ) \\<br /> <br /> &amp; = \frac{\lambda}{2} \eta^{\mu \nu} \left[ ( \partial_{\sigma}A^{\sigma} )<br /> + <br /> ( \partial_{\rho}A^{\rho} ) \right] \\<br /> <br /> &amp; = \lambda \eta^{\mu \nu} ( \partial_{\sigma}A^{\sigma} ) \\<br /> <br /> \end{align*}<br />

Now I was hoping to get:

<br /> \lambda \partial^{\nu} A^{\mu}<br />

as ultimately I need the EL equations to give me:

<br /> \begin{align*}<br /> \frac{\partial \mathcal{L}_{\xi}}{\partial A_{\nu}} - \partial_{\mu} \left( \frac{\partial \mathcal{L}_{\xi}}{\partial (\partial_{\mu} A_{\nu})} \right)<br /> &amp;=\Box A^{\nu} - \partial^{\nu} ( \partial_{\mu} A^{\mu} ) - \lambda \partial^{\nu}(\partial_{\mu} A^{\mu}) \\<br /> &amp;= \Box A^{\nu} - ( 1 + \lambda ) \partial^{\nu} ( \partial_{\mu} A^{\mu} ) \\<br /> &amp;= 0<br /> \end{align*}<br />

Can anyone show me where I've gone wrong? I didn't stick this in the homework section as it's not homework. I'm just trying to work through the through missing steps from the text I'm reading.

Thanks in advance
 
Last edited:
Physics news on Phys.org
edit... now I'm finished stating the question.
 
Last edited:
Irrational, You've got exactly what you need. :smile: Well, up to a minus sign anyway. You've got λ ημν(∂σAσ). So plug this into the Euler-Lagrange equation:
-∂μ(λ ημν(∂σAσ)) = -λ ∂ν(∂σAσ) = -λ ∂ν(∂μAμ)
 
you have no idea how thick i feel right now. thanks for filling in the gap.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top