Elastic collision, 2 objects collide.

AI Thread Summary
In an elastic collision scenario, an object with a mass of 9.4 kg moving east at 15.3 m/s collides with a stationary object, resulting in the first object recoiling at -5.3 m/s. The initial calculation for the mass of the second object was proposed as 35.9 kg, but this was identified as incorrect. The formula used for the calculation was noted to have missing parentheses, which affected the outcome. Clarifications were sought regarding the variables in the formula and the values plugged in. The discussion highlights the importance of proper formula application in solving collision problems.
IDKPhysics101
Messages
31
Reaction score
0
Object 1 has a mass of 9.4 kg and is moving eastward with a velocity of 15.3 m/s. It collides with a stationary object. After the collision object 1 recoils with a velocity of -5.3 m/s What is the mass (in kg) of object 2?

m2=35.9kg?

I don't have time to type my work right now. But will show work if answer is wrong to see where i went wrong.
 
Physics news on Phys.org
It is wrong.

ehild
 
i used the equation v2=(2m1/m1+m2)vo1 - (m1-m2/m1+m2)vo2
 
You missed some parenteses in the formula. It is wrong without them.

Do you know the meaning of the letters in that formula? What numbers did you plug in?

ehild
 
i think i screwed up getting m2 by itself but i had plugged my numbers in as...

-5.3=((2*9.4)/(9.4+m2))*(15.3)-0
 
-5.3 is the velocity of the object 1. You do not know v2.

ehild
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
6
Views
2K
Replies
3
Views
753
Replies
5
Views
2K
Replies
4
Views
2K
Replies
13
Views
1K
Replies
16
Views
3K
Replies
4
Views
2K
Back
Top