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## Homework Statement

On a frictionless surface, a 0.35 kg puck moves horizontally to the right (at an angle of 0°) and a speed of 2.3 m/s. It collides with a 0.23 kg puck that is stationary. After the collision, the puck that was initially moving has a speed of 2.0 m/s and is moving at an angle of −32°. What is the velocity of the other puck after the collision?

## Homework Equations

Momentum before= momentum after

kinetic energy before= kinetic energy after

AB=AB cos (x)

## The Attempt at a Solution

From Momentum before= momentum after, I got

M1=first mass

Vi1=initial velocity of the first mass

Vf1=final velocity of the first mass...and I think you get the rest

M1(Vi1-Vf1)=(M2)(Vf2)

From the kinetic energy before= kinetic energy after, i got

M1(Vi1^2-V1f^2)=(M2)(V2f^2)

Now i'm kinda lost on what to do...some advice?

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