1. The problem statement, all variables and given/known data On a frictionless surface, a 0.35 kg puck moves horizontally to the right (at an angle of 0°) and a speed of 2.3 m/s. It collides with a 0.23 kg puck that is stationary. After the collision, the puck that was initially moving has a speed of 2.0 m/s and is moving at an angle of −32°. What is the velocity of the other puck after the collision? 2. Relevant equations Momentum before= momentum after kinetic energy before= kinetic energy after AB=AB cos (x) 3. The attempt at a solution From Momentum before= momentum after, I got M1=first mass Vi1=initial velocity of the first mass Vf1=final velocity of the first mass...and I think you get the rest M1(Vi1-Vf1)=(M2)(Vf2) From the kinetic energy before= kinetic energy after, i got M1(Vi1^2-V1f^2)=(M2)(V2f^2) Now i'm kinda lost on what to do...some advice?