On a frictionless surface, a 0.35 kg puck moves horizontally to the right (at an angle of 0°) and a speed of 2.3 m/s. It collides with a 0.23 kg puck that is stationary. After the collision, the puck that was initially moving has a speed of 2.0 m/s and is moving at an angle of −32°. What is the velocity of the other puck after the collision?
Momentum before= momentum after
kinetic energy before= kinetic energy after
AB=AB cos (x)
The Attempt at a Solution
From Momentum before= momentum after, I got
Vi1=initial velocity of the first mass
Vf1=final velocity of the first mass...and I think you get the rest
From the kinetic energy before= kinetic energy after, i got
Now i'm kinda lost on what to do...some advice?