Elastic potential energy of vertical spring

AI Thread Summary
The discussion revolves around calculating the spring constant and potential energy associated with various spring configurations. Key problems include determining the force constant of a spring when a mass compresses it, calculating work done to compress a spring, and analyzing the effects of cutting a spring into two. Additionally, participants emphasize the importance of showing work for each problem to facilitate understanding and avoid confusion. The thread highlights the application of Hooke's law and the relationship between force, displacement, and energy in springs.
Vanessa22
Messages
2
Reaction score
0
help is urgently needed please and thank u.

1. When a 13.2-kg mass is placed on top of a vertical spring, the spring compresses 5.93 cm. Find the force constant of the spring.

2. If a spring has a spring constant of 400 N/m, how much work is required to compress the spring 25.0 cm from its undisturbed position?

3. A compressed spring that obeys Hooke's law has a potential energy of 18 J. If the spring constant of the spring is 400 N/m, find the distance by which the spring is compressed.

4. An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The string stretches by 0.165 m. The spring is then cut into two identical springs of 50 coils each. Each spring is attached between the ceiling and the object. By how much does each spring stretch?

5. A vertical spring stretches 10 cm under a load of 200 g.
a. Determine the spring constant.
b. How much work is required to stretch the first 5 cm.
c. How much work is required to stretch the last 5 cm.

6. A mass sitting on a horizontal frictionless surface is attached to one end of spring; the other end of the spring is fixed to a wall. To compress the spring by 0.12 m requires 3.0 J of work. If the mass is released from rest with the spring compressed, it experiences a maximum acceleration of 15 m/s/s. Find the value of the spring constant.

7. To compress spring 1 by 0.20 m takes 150 J of work. Stretching spring 2 by 0.30 m requires 210 J of work. Which spring is stiffer?
 
Physics news on Phys.org
Hi Venessa, Welcome to PF

1) we need to see your work using the homework template
2) we need to see each problem in it own thread otherwise you'll get a tangled mess of intertwining comments
3) We can't help you if you don't show your work

-source: jedishrfu:smile:
 
4.An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The string stretches by 0.165 m. The spring is then cut into two identical springs of 50 coils each. Each spring is attached between the ceiling and the object. By how much does each spring stretch?
- x= 1/2x100/0.165
=50/0.165
=303.03m

6. A mass sitting on a horizontal frictionless surface is attached to one end of spring; the other end of the spring is fixed to a wall. To compress the spring by 0.12 m requires 3.0 J of work. If the mass is released from rest with the spring compressed, it experiences a maximum acceleration of 15 m/s/s. Find the value of the spring constant.
- k=f/x
=3/0.12
=25 n/m

7.To compress spring 1 by 0.20 m takes 150 J of work. Stretching spring 2 by 0.30 m requires 210 J of work. Which spring is stiffer?
-
a. k=f/x
=150/0.20
=750 n/m

b. k=f/x
=210/0.30
=700 n/m
~so the stiffer spring would be spring number 2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top