Electric AC Generator: Understand Magnetic Fields & Brushes

AI Thread Summary
When the armature of an AC generator is perpendicular to the magnetic field, no current is generated because the magnetic flux linked with the coil is not changing, resulting in no induced electromotive force (emf). Brushes are typically used in conjunction with a commutator to convert an AC generator into a DC generator, but their necessity can vary depending on the generator design. If the magnets are stationary and the wire loop rotates, brushes help prevent the leads from twisting excessively. Alternatively, using permanent magnets with a fixed loop can also generate AC without the need for brushes. Understanding these principles clarifies the operation of electric AC generators.
genevievelily
Messages
16
Reaction score
0
Hi! I have been studying AC generators. I am confused about why there is no current when the armature is perpendicular to the magnetic field (when it is vertical). Also, what is the purpose of the brushes? Probably a really obvious answer, but it is confusing me. Any help would be appreciated, thanks!
 
Physics news on Phys.org
Are you considering a single flat coil rotating in a uniform magnetic field? If so, when the coil is in the position you describe its area is perpendicular to the field at this instant, so its area projected on to a plane at right angles to the field is a maximum and, at this instant, not changing. So the magnetic flux linked with the coil is not changing. So there is no induced emf.

Can't think why there should be brushes, unless there is also a commutator to turn the ac generator into a dc generator. Alternatively we're dealing with a different sort of ac generator from the simple type I assumed in the first paragraph.
 
Philip Wood said:
Can't think why there should be brushes

If the magnets are stationary and the loop of wire rotates, you need some mechanism to keep the leads to the loop from twisting around themselves ad infinitum, no?

Alternatively, you could use permanent magnets and a fixed loop, and rotate the magnets instead.
 
I was being stupid. Not for the first time.
 
Don't worry. We all end up wearing the dunce cap sometimes, myself included. :rolleyes:
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top