1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric Charges and Forces

  1. Oct 25, 2005 #1
    A small metal plate is bolted to the ceiling, and an "electron pump" is connected between the metal plate and yourself (mass of 60 kg). The pump starts pumping electrons from the metal plate to you.
    How many electrons must be moved from the metal plate to you in order for you to hang suspended in the air 2.0 m below the ceiling? HINT: Assume that both you and the plate can be modeled as point charges.
    My diagram is as such:
    - - -


    The electrons move downward, toward me. However, I am confused as to where the charge is directed. Is it directed toward me or toward the metal plate? (Since charges move toward the negative charge.

    So we have:
    [tex]m = 60 kg[/tex]
    [tex]r = 2.0 m[/tex]
    [tex]q_e = 1.6 * 10^{-19} C[/tex]
    [tex]k = 9 * 10^{9} \frac{Nm^2}{C^2}[/tex]
    [tex]n = number of electrons[/tex]

    The net force must be zero since I am suspended in the air at this point and am not moving, therefore:
    [tex]F_{net}=F_q - F_g[/tex]
    [tex]F_q = F_g[/tex]
    [tex]\frac{kqn}{r^2} = mg[/tex]
    [tex]n = \frac{mgr^2}{kq} = 1.6 * 10^{12} electrons[/tex]
    However, this is the wrong answer.
    The answer in the textbook is [tex]3.2 * 10^{15}[/tex]. What is wrong with my method?

    Is there an electric force coming from myself also? If so, what is it?

    ALSO: If you happen to know anything about sound interference/light waves, please post in the other two threads started by my boyfriend, as he is in desperate need right now of answers but no one wants to reply to his threads for some reason. His posts are under the name "dekoi" also. Thank you.
    Last edited by a moderator: Oct 26, 2005
  2. jcsd
  3. Oct 26, 2005 #2
    Anyone? .
  4. Oct 26, 2005 #3

    Doc Al

    User Avatar

    Staff: Mentor

    Your error is in applying Coulomb's law, which is:
    [tex]F = \frac{k q_1 q_2}{r^2}[/tex]
    (You only included one of the charges.)
  5. Oct 26, 2005 #4
    I know that's where I am confused.
    I don't know what the charge on myself is. At first I thought it was 0, since a human does not have a charge.
    But then I thought that if the electrons are holding me up, then I must have a positive charge.
    A positive charge equal to the electron charge?

    That's what I don't know.
  6. Oct 26, 2005 #5

    I got it.

    My error was when I made the positive charge equal to the electron charge, I forgot to square the number of electrons, since it applies to both charges.

    And the positive charge HAS to be equal to the electron charge or else I would not be in equilibrium. Right?
  7. Oct 26, 2005 #6

    Doc Al

    User Avatar

    Staff: Mentor

    The reason the positive charge must equal the negative charge is due to the conservation of charge. For every electron moved, you gain -e of charge, but the plate (which loses the electron) gets +e of charge.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Electric Charges and Forces