Electric Field and Force between two plates [general question]

• Samurai44
In summary, the conversation discusses the difference in calculating the electric field or force between two charged plates, depending on whether both plates are connected to a power source or if one plate is also earthed. It is mentioned that the potential difference is the key factor in determining the result, and that the potential difference between the plates will be 6 volts in the given scenario. The formula for finding the force on a charge between the plates is also mentioned, with the value of V being 6 in this case. The distinction between Potential and Potential Difference is also briefly mentioned, with the understanding that Earth Potential is considered as zero in such calculations.

Samurai44

Greetings, I am just confused in something , Is there a difference when calculating the electric field , or a force exerted on a charge between two plates , if the two plates were :
a) both plates are charged ( connected to a power source) ,
OR
b) both plates are charged ( connected to a power source), but the negative plate is earthed , i.e 0 V at the negative plate .

It only depends upon the Potential Difference (as long as there is no other structure nearby). SO connecting between +6V and -6V will give the same result as +12V and earth.

sophiecentaur said:
It only depends upon the Potential Difference (as long as there is no other structure nearby). SO connecting between +6V and -6V will give the same result as +12V and earth.
i mean let's suppose the voltage is 6V at the + plate , but the negative plate is 0v because its earthed

Samurai44 said:
i mean let's suppose the voltage is 6V at the + plate , but the negative plate is 0v because its earthed
In that case the potential difference will be 6 volts.

Doc Al said:
In that case the potential difference will be 6 volts.

so when finding a force on a charge(e .g an electron) between the plates , for example at the mid , using this formula "F=e V/d" ,, do we use the value of V as 6 ?

Samurai44 said:
so when finding a force on a charge(e .g an electron) between the plates , for example at the mid , using this formula "F=e V/d" ,, do we use the value of V as 6 ?
Field is Volts per Metre. If you have 6V PD between the plates then it's 6V for the formula.
I am just wondering if you could be worrying about the distinction between Potential and Potential Difference. When dealing with situations on Earth then you take Earth Potential as Zero and 'Potential' is relative to Earth. If the minus terminal of the supply is connected to Earth , the 'Potential' of the + terminal is 6V - and vice versa, when connecting the other way round.

1. What is an electric field?

An electric field is a region in which a charged particle experiences a force. It is created by a charged object and is measured in units of volts per meter (V/m).

2. How do electric fields form between two plates?

Electric fields form between two plates when one plate has a positive charge and the other has a negative charge. The charges attract each other and create an electric field between them.

3. How is electric force calculated between two plates?

The electric force between two plates is calculated using the equation F = Eq, where F is the force in Newtons, E is the electric field strength in volts per meter, and q is the charge in Coulombs.

4. Can the electric force between two plates be zero?

Yes, the electric force between two plates can be zero if the plates have equal and opposite charges and are placed a certain distance apart. In this case, the electric forces cancel each other out, resulting in a net force of zero.

5. How is the direction of the electric field between two plates determined?

The direction of the electric field between two plates is determined by the direction in which a positive test charge would move if placed in the field. The field always points from positive to negative charges.