Electric Field and Potential Calculation for Square of Charges | Coulomb's Law

  • Thread starter Thread starter Clara Chung
  • Start date Start date
  • Tags Tags
    Electrostatics
AI Thread Summary
The discussion focuses on calculating the electric field and potential at the center of a square formed by four point charges. The electric field was calculated to be 76.3 x 10^3 NC^-1 directed upward. For the electric potential, the initial attempt yielded a value that was one-third of the expected result, prompting a request for clarification on the calculation method. It was suggested to use the definition of electric potential as the work done per charge from infinity to the center, emphasizing that voltage is a scalar quantity. The conversation highlights the importance of correctly applying Coulomb's law and understanding the principles of electric fields and potentials.
Clara Chung
Messages
300
Reaction score
13

Homework Statement


Four point charges are placed at the corners of a square of side 1m as shown in Fig 18.54 Find
a) the electric field, and
b) the electric potential at the center of the square

Photo is attached

Homework Equations


coulomb's law
Ans of a=76.3 x 10^3 NC^-1 upward
Ans of b=-25.4x 10^3 V

The Attempt at a Solution


I can do part a by 2x(2/10^6)x2x8.99x10^9xsin45 + 2x(2/10^6)x8.99x10^9xsin45=76.3 x 10^3 NC^-1 upward.
I just attempted b part by 2x(2/10^6)xroot2x8.99x10^9xsin45 + 2x(1/10^6)xroot2x8.99x10^9xsin45
because V=ED I just multiply each term by its length 1/root2 from the center.
But the answer seems to be one third of the answer from part a, please teach me how to do.
 

Attachments

  • Untitled.png
    Untitled.png
    9.7 KB · Views: 472
Physics news on Phys.org
Try doing it from the definition of the electric potential.
 
  • Like
Likes Clara Chung
Use the definition: work done per charge from infinity to the center?
 
Clara Chung said:
Use the definition: work done per charge from infinity to the center?
That will work. Potential at a point at a distance r due to a charge q is kq/r. You can add and subtract potentials aglebraically.
 
  • Like
Likes Clara Chung
Thanks I forget that voltage is scalar
 
  • Like
Likes Simon Bridge
Well done.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top