Electric Field from Gauss' Law - Vector Form

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Gauss' Law can be used to find the electric field from a charge distribution, but it is most effective when symmetry is present. For symmetrical cases, such as a point charge or uniformly charged sphere, the electric field can be derived directly from the law by considering the electric flux through a Gaussian surface. However, when symmetry is absent, Gauss' Law does not provide enough information to uniquely determine the electric field at a point. In such scenarios, the electric field may be zero, but this does not imply the absence of charges elsewhere; for example, the electric field inside a uniformly charged shell is zero despite the presence of charge on the shell's surface. Understanding the limitations of Gauss' Law is crucial for accurately applying it to different charge configurations.
roshan2004
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Gauss' Law-Can't we find the Electric Field (In the vector form) from Gauss' Law? Because in most of the problems I have been doing like the case of a Charge in a solid sphere, I can find the Magnitude of Electric Field by Gauss' Law but not the Electric Field. Am I wrong here?
 
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You can use Gauss' Law to find the electric field due to a given charge distribution. However, it is very limited because Gauss' Law only deals with the divergence of the electric field. If you convert this to an integral equation, then it relates the total enclosed charge to the electric flux through a Gaussian surface.

If we have a problem that we can capitalize on symmetry, then we can sometimes solve for the electric field. For example, given that we have a point charge in space, we can choose a spherical shell as our Gaussian surface. Then, we know by symmetry that the electric field vectors must be normal to the Gaussian surface. Thus, the flux through the surface at a given point is equal to the sign and magnitude of the electric field vector. From this we can derive the electric field due to a point source. Likewise, we can use this again for any spherically symmetric charge distribution (like a uniform charge density spread across a sphere's surface or volume).

But once we lose these symmetries, then the flux will not be enough to uniquely define the electric field.
 
The electric field at a given point is found to be a zero. is it true to say that there are no charges in other point. justify the answer please with example.
 
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