Electric Field in a Square Problem

AI Thread Summary
The discussion focuses on calculating the electric field at point C in a square configuration due to charges A, B, and D. The direction of the electric field was determined to be West based on vector diagrams showing the attraction and repulsion of charges. The magnitude of the electric field was calculated using the formula E = kq/r^2, leading to a final expression of 4√2 kq/a^2 after correcting for vector addition. There is uncertainty about how to approach the calculation for the electric field due to charge B, with a suggestion to apply the superposition principle and vector addition for clarity. The conversation emphasizes the importance of accurately summing vector components and understanding the geometry of the problem.
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Homework Statement



I think it would be better if I put the picture.

nTzgs.png


Additional questions:
Find the direction of the electric field.
Find the magnitude of electric field due at C due to charges A, B, and D.

Oq2YY.png

Homework Equations



Pythagorean Theorem.
E = kq/r^2

The Attempt at a Solution



For the first problem, I drew vector diagrams based on the charges at the center of the square. I ended up having 4 arrows:
O -> A (electron attraction)
O -> D (electron attraction)
O -> A (proton repulsion of charge C)
O -> D (proton repulsion of charge D)
So basically I had 2 visual arrows of pointing NW and SW from the origin. This makes the direction of the electric field to be West. Thats basically the part I only got.
For the magnitude of the electric field I used E = kq/r^2 . I know r = [√(2)/2]a. Now I got lost on what to really do (I tried a bunch of stuff but it didn't really make sense to me). The final answer for the first question is 4√2 kq/a^2
 
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Do you know how to sum vectors? eg Work out the x and y component of each vector. Sum all the x components and sum all the y components etc

To further simplify the equations it might help to remember that:

This is a square so 45 degree angles are involved.
cos(45)=sin(45)=0.5*SQRT(2)
Pythagorous involves squares and square roots

sorry if you know all that.
 
Thanks for the reply!

All along I was doing my math wrong on adding the electric field vectors.

As r = (sqrt2/2)a

e = kq/(r^2)
e = kq/(a^2/2)
e = 2kq/(a^2) for each vector on one side.

Since there's 2 vectors on each side then it equals to 4kq/(a^2)

Combining the vectors using parallelogram rule I get 4sqrt2 kq/(a^2)

For the third question (Find the magnitude of electric field due at C due to charges A, B, and D):
Do I just solve this problem similar to the 1st question? (draw vectors based on the center O). I drew the vectors due to C and here's what I came up with:

C -> A
C -> D
B -> down

Not sure if I'm starting this correctly. Do I just add the electric field vectors again based on the superposition rule? If so how would I do the vector pointing north from B (not sure what I would put for as r).
 
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