Electric field in the center of uniformly polarized cylinder

AI Thread Summary
The discussion revolves around calculating the electric field intensity at the center of a uniformly polarized hollow dielectric cylinder. The polarization vector is directed normally to the bases, and the surrounding medium is vacuum. An initial approximation suggests that the electric field could be calculated using E = -P/ε0, akin to the field between two oppositely charged planes, but the dimensions of the cylinder are unknown. The expected result for the electric field is E = -Ph(1/(√a²+h²) - 1/(√b²+h²)) / ε0. The presence of effective surface charge density due to polarization on parts of the cylinder's surface is also noted.
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Homework Statement


Hollow dielectric cylinder, with inner radius a, outer radius b, and height 2h is uniformly polarized by volume. Polarization vector is normal on the bases of a cylinder. Intensity of polarization vector is given, P. The surrounding area is vacuum. Calculate intensity of electric field in center of the cylinder (at point C)

Homework Equations


-Cylindrical geometry
-Polarization vector

The Attempt at a Solution


If approximated, intensity of electric field could be E= -P/ε0 (field between two oppositely charged planes). But, we don't know the exact values for dimensions of a cylinder. Could someone give a hint on this, I am stuck here for a while.

The result should be E= -Ph( 1/(√a2+h2)-1/(√b2+h2)) / ε0

Thanks for replies.
 

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Certain parts of the surface of the cylinder will have an effective surface charge density due to the polarization.
 
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