Electric field just beyond surface of proton

AI Thread Summary
To find the electric field just beyond the surface of a proton, it is treated as a uniformly charged sphere with a radius of 1.0 x 10^-15 m. The relevant equation used is E = (1/4piE0)(Q/r^2), where E0 is the permittivity of free space. The charge of the proton is equal in magnitude but opposite in sign to that of an electron. The solution can also be derived using Gauss's law. The approach and calculations appear to be correct based on the principles of electrostatics.
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Homework Statement



If a proton is considered a uniform ball of charge of radius 1.0x10-15m, what is the
electric field just beyond its surface?


Homework Equations



Gauss's law?

The Attempt at a Solution



I followed a problem in the book that found an equation for the electric field of a uniformly charged sphere. I treated the proton as a uniform sphere of charge, so that the same equation could be applied.

The equation was E = (1/4piE0)(Q/r^2)

*E0 is constant 8.85 x 10^-12.

So I just plugged in charge of electron and radius r of the proton.
 
Last edited:
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That looks fine. The result can of course be derived from Gauss' law. Remember that a proton has the same magnitude of charge as an electron but different sign.
 

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