Electric Field Magnitude at Point P Inside a Charged Sphere

AI Thread Summary
The discussion focuses on calculating the electric field magnitude at point P inside a uniformly charged insulating sphere using Gauss' Law. The initial approach involved determining the enclosed charge and applying the law, but the calculations yielded incorrect results. Participants suggest breaking down the problem into logical steps, emphasizing the importance of finding the fraction of total charge within the inner spherical volume. The correct formulation involves using the ratio of the volumes and the total charge to derive the electric field. Ultimately, the conversation highlights the need for careful application of Gauss' Law and proper organization of calculations.
eurekameh
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An insulating solid sphere of radius a = 1.2 m is uniformly charged with charge Q = 4.5 x 10^-6 C. Point P inside the sphere is at a distance r = 0.60 m from the sphere center C. What is the magnitude of the electric field at point P?

So I'm using Gauss' Law:

q,enc = Q[(pi * r^2)/ (pi * a^2)]

int(E dot dA) = q,enc / epsilon,naut
= Q[(pi * r^2)/ (pi * a^2)] / epsilon,naut

E * (pi * r^2) = Q(r^2 / a^2) / epsilon,naut

Thus, E = (Q) / (pi * epsilon,naut * a^2) = 1.12 * 10^5 V/m.

This doesn't seem to be the answer. Anyone know what I did wrong?
 
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Volume varies as the cube of the radius.
 
Now I'm doing E * pi * r^2 = (Qr^3) / (epsilon,naut * a^3), but E is turning out to be 5.62E4 V/m, which is 4 times the correct answer.
 
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?
 
r^3 / a^3
 
gneill said:
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?

eurekameh said:
r^3 / a^3

Okay, so given that you know the total charge Q, you now know the fraction of that charge that's within the spherical region with radius r.

Now, given a charge q within that sphere of radius r, what's the resulting electric field at distance r from its center?
 
E = (Qr) / (pi * a^3)
 
Edit:
E = (Qr) / (pi * a^3 * epsilon,naut)
 
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.
 
  • #10
eurekameh said:
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.

So choose your Gaussian surface and write Gauss' law for for it. You'll find that you need the total charge enclosed by the surface (done above), and the volume of the Gaussian sphere (done above). I suppose it's just a matter of putting the steps in an order that shows the appropriate progression :smile:
 
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