Electric field on a one dimensional line

AI Thread Summary
To calculate the electric field at point X0, which is greater than the length L of a uniformly charged line, the correct approach involves integrating the contributions from each infinitesimal charge element along the line. The initial attempt mistakenly used a constant distance in the formula, while the distance should vary based on the position of the charge element. The correct expression for the electric field incorporates the varying distance and results in the formula (Q/(4*pi*E0))*(1/(L(X0 - L)) - 1/(L*X0)). The key correction is recognizing that the distance r between the charge element and point X0 changes as you integrate from 0 to L. Understanding this variation is crucial for accurately calculating the electric field.
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Homework Statement



An electric charge Q has been evenly divided over a line with the length L. Calculate the electric field in the field spot X0. X0 > L

Homework Equations





The Attempt at a Solution



E = 0SL(dQ/(4*pi*E0*X0^2))

0SL = the integral over 0 to L >_<

dQ = Q*dx/L , I think...

E = (Q/(4*pi*E0*(X0^2)*L))*0SL(dx)

E = (Q/(4*pi*E0*(X0^2)*L))*L

this is not a correct answer so i wonder where I am failing.


The right answer should be (Q/(4*pi*E0))*(1/(L(X0 - L)) - 1/(L*X0))
 
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3. The Attempt at a Solution

E = 0SL(dQ/(4*pi*E0*X0^2))

The equation

E = \frac{1}{{4\pi {\varepsilon _0}}}\int_0^L {\frac{{dQ}}{{{x_0}^2}}}

has an error in it.

dQ = Q*dx/L , I think...

This is correct.

Your first equation just needs a small modification. As it currently stands, your equation has constant "r", but r is supposed to be the distance between dx and x_0, and the position of dx varies between 0 and L.
 
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