Electric field problem -- Repulsive force between two charged spheres

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Dezzi
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Homework Statement
Two identical spheres have charges q1 and q2. When they are 20 cm apart, the replusive force between them is 1.35×10^‐4N. After they touched together and separated once again to 20cm, the replusive force between them is 1.406×10^-4N. FIND q1 and q2. (Ans 20nC; 30 nC)
Relevant Equations
F=kQ1Q2/r^2
I attempt to solve the problem in the picture below.
 
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  • Printed physics problem 6: two identical spheres with charges q1 and q2 are 20 cm apart with repulsive force 1.35 x 10^-4 N; after touching and separating to 20 cm, force is 1.406 x 10^-4 N. Find q1 and q2.
    Screenshot_20211031-145927_Drive.jpg
    14 KB · Views: 168
  • Handwritten derivation rotated sideways: F = kQ1Q2/r^2 rearranged to Q1Q2 = Fr^2/k, then Q1 = Q2, Q = sqrt((20 x 10^-3)(1.35 x 10^-4)/(9 x 10^9)) = sqrt(6 x 10^-16 C^2) = 2.45 x 10^-8 C, and a second line with 1.40 x 10^-4 giving sqrt(6.25 x 10^-16 C^2) = 2.5 x 10^-8 C.
    16357071656697539725904243983068.jpg
    25.8 KB · Views: 186
PeroK said:
Why is the force different the second time?
The question say " they touched together and separated once again"
 
PeroK said:
So, what changed?
I guess the charges get equalised. So, you've worked out that average charge: ##2.5 nC##, which looks right.

The hard bit is to figure out what the original charges were. Any ideas?
 
A quibble: since the spheres are evidently conductors, the question ought to specify that the spheres are much smaller than 20cm radius. Otherwise the charge distributions complicate matters.
 
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