Electric field stregth between charges

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SUMMARY

The discussion focuses on calculating the electric field strength between two point charges, specifically a +60μC charge and a -30μC charge, as well as a 75μC charge and a -25μC charge, both separated by 2.0 meters. The correct formula used is E = kQ/r², where k is the electrostatic constant. The confusion arises from the interpretation of the negative sign in the electric field calculations, which indicates direction rather than magnitude. The correct total electric field strength for the second scenario is 9.0 x 10^5 N/C towards the negative charge, confirming that the negative sign should be disregarded when summing magnitudes.

PREREQUISITES
  • Understanding of Coulomb's Law and electric field calculations
  • Familiarity with the electrostatic constant (k = 8.99 x 10^9 N m²/C²)
  • Basic knowledge of charge polarity and its effect on electric field direction
  • Ability to perform algebraic calculations involving scientific notation
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  • Study the concept of electric field lines and their representation for positive and negative charges
  • Learn about superposition principle in electric fields for multiple charges
  • Explore the implications of charge magnitude and distance on electric field strength
  • Investigate practical applications of electric fields in real-world scenarios, such as capacitors and electric circuits
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GRAvit__
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1. What is the magnitude and direction of the electric field strength midway between a +60uC charge and a -30uC charge, if the charges are 2.0m apart?

2.E=kQ/r^2

3.
E1=Kx-30u/1
E2=-2.75x10^5

E2=kx60u/1
E2=5.4x10^5

Etotal=E1 + E2 ----> 2.7x10^5 N/C towards the - charge (my book says i have this right)

The problem that i have is that i came across a question that's almost the same but different answer.

1. What is the magnitude and direction of the electric field strength midway between a 75uC charge and a -25uC charge, if the charges are 2.0m apart?

Now i did everything the same as the first one and came to

E1=kx-25u/1
E1=-2.25x10^5

E2=kx75u/1
E2=6.75x10^5

Etotal=E1+E2 ----> 4.5x10^5 N/C towards the - charge (my book says its wrong)

Book answer : 9.0x10^5

which would work if i took away the (-) from -2.25x10^5 and added them up but that's a different way of doing it from the first so I'm confused as to which way is right.

The only difference in the questions that i see is there's no (+) in front of the 75uC

Thanks for any help you can give me
 
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GRAvit__ said:
1. What is the magnitude and direction of the electric field strength midway between a +60uC charge and a -30uC charge, if the charges are 2.0m apart?

2.E=kQ/r^2

3.
E1=Kx-30u/1
E2=-2.75x10^5

E2=kx60u/1
E2=5.4x10^5

Etotal=E1 + E2 ----> 2.7x10^5 N/C towards the - charge (my book says i have this right)

The problem that i have is that i came across a question that's almost the same but different answer.

1. What is the magnitude and direction of the electric field strength midway between a 75uC charge and a -25uC charge, if the charges are 2.0m apart?

Now i did everything the same as the first one and came to

E1=kx-25u/1
E1=-2.25x10^5

E2=kx75u/1
E2=6.75x10^5

Etotal=E1+E2 ----> 4.5x10^5 N/C towards the - charge (my book says its wrong)

Book answer : 9.0x10^5

which would work if i took away the (-) from -2.25x10^5 and added them up but that's a different way of doing it from the first so I'm confused as to which way is right.

The only difference in the questions that i see is there's no (+) in front of the 75uC

Thanks for any help you can give me
Your answer to the first problem is wrong too. The book is also wrong if it agreed with you.

Does the electric field due to a positive charge point towards it, or point a way from it?

Does the electric field due to a negative charge point towards it, or point a way from it?
 
The electric field would point away from a positive charge

The electric field would point towards a negative charge
 
(-)-------(m)---------(+)
<----- ...<-------

So you would just take out the negative and add it up? Negative is only referring to direction in this case?
 
GRAvit__ said:
(-)-------(m)---------(+)
<----- ...<-------

So you would just take out the negative and add it up? Negative is only referring to direction in this case?

Yes.

or they're both negative.
 

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