Three charges, q1 = 8.59nC, q2 = -5.67nC and q3 = 2.98nC are at the corners of an equilateral triangle, as shown in the figure below.
The angle alpha is 60.0° and L = 0.537 m. We are interested in the point midway between the charges q1 and q2 on the x axis.
For starters, calculate the magnitude of the electric field due only to charge q3 at this point
F = k (qa)(qb)/r^2
E = k (q)/r^2
E = F/q0
The Attempt at a Solution
Okay so Im at an utter loss... I thought at first you should find all the Forces from each point on 3. using the first equation. And so well I did that. Then I took those forces and used the angle of 60 degrees to get them all going in the same direction that way I could get the net force. After gaining the net force I used the x and the y to find the magnitude of the net force. Then I used the 3rd equation listed. so I divided the F by q3 and recieved an answer. But I feel like my thought process is wrong. I don't have a scanner or anything. Or I would upload my hand written work. But I typed each step that I took.