- #1

maiad

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https://www.smartphysics.com/Content/Media/Images/EM/03/h3_lineD.png

In the image above, i was asked to find the electric field at point P. since the y-components cancel due to symmetry, i used he equation [itex]\Phi[/itex]=[itex]\int[/itex]E dA=Qenclosed/[itex]\epsilon[/itex] .

I found q1 and q2 by multiplying (charge density x h). then from that, i added the charges up to get Q(enclosed). I found my E by [itex]\Phi[/itex]/(2πah).

This method was wrong apparently but i don't know why. can someone explain?

Is it because the electric field through the surface is not uniform?

I later used superposition instead and i got the right answer.

In the image above, i was asked to find the electric field at point P. since the y-components cancel due to symmetry, i used he equation [itex]\Phi[/itex]=[itex]\int[/itex]E dA=Qenclosed/[itex]\epsilon[/itex] .

I found q1 and q2 by multiplying (charge density x h). then from that, i added the charges up to get Q(enclosed). I found my E by [itex]\Phi[/itex]/(2πah).

This method was wrong apparently but i don't know why. can someone explain?

Is it because the electric field through the surface is not uniform?

I later used superposition instead and i got the right answer.

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