Electric Force and Potential Energy Calculations

AI Thread Summary
The discussion focuses on calculating electric potential, work done, electric force, and electric field between two charged objects. The electric potential at point P, 0.30 meters from object I, is determined to be 9.0 x 10^4 V. For the work done in bringing object II from infinity to point P, the formula W = Vq2 is suggested, leveraging the potential calculated earlier. The magnitude of the electric force between the two objects and the electric field at the midpoint are also discussed, with the user expressing confidence in solving the remaining parts of the problem. The thread emphasizes the application of fundamental equations in electrostatics to find the required values.
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Homework Statement


Object I has a charge of + 3 x 10^6 coulomb and a mass of 0.0025 kilogram.

a. What is the electric potential at point P, 0.30 meter from object I ?

Object II, of the same mass as object I, but having a charge of + 1 x 10^6 coulomb, is brought from infinity to point P, as shown above.

b. How much work must be done to bring the object II from infinity to point P ?

c. What is the magnitude of the electric force between the two objects when they are 0.30 meter apart?

d. What are the magnitude and direction of the electric field at the point midway between the two objects?

The two objects are then released simultaneously and move apart due to the electric force between them. No other forces act on the objects.

e. What is the speed of object I when the objects are very far apart?



Homework Equations


V = ke*(q/r)
\DeltaPE = -WAB = -qEx\Deltax


The Attempt at a Solution


a. V = ke*(q/r) = 9.0*10^4 V

For b, would you use:
-WAB = -qEx\Deltax ?

Your help is appreciated.
 
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science.girl said:
For b, would you use:
-WAB = -qEx\Deltax ?

You can, but usually you use W = qΔV. In this case this seems easier since you already know V at P from part a.
 
My apologies... the answer was much easier than I had originally thought!

W = Vq2

I believe I have it from here.
 
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