What Are the Directional Angles for Electric Forces in an Equilateral Triangle?

AI Thread Summary
The discussion focuses on calculating the net electric forces acting on three positive charges located at the corners of an equilateral triangle. Each charge has a magnitude of 11.0 µC and is positioned at the vertices of a triangle with a side length of 14.0 cm. The calculated force magnitude for each charge is approximately 55.561 N. While the angle for the force on Q1 is identified as 90 degrees, the user seeks clarification on determining the directional angles for Q2 and Q3. The conversation emphasizes the need for understanding the vector nature of forces in an equilateral triangle configuration.
Bensky
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Electric force angles problem :(

Homework Statement


Three positive particles of charges 11.0 µC are located at the corners of an equilateral triangle of side d = 14.0 cm (Fig. 16-38). Calculate the magnitude and direction of the net force on each particle.
16-38alt.gif

Fig. 16-38

Homework Equations


F = KQ_1Q_2/r^2

The Attempt at a Solution


F = KQ_1Q_2/r^2
F = (9X10^9)(1.1X10^-5)^2/.14^2
F = 55.561 N for all points - Q1, Q2, and Q3 (correct)

Q1 angle = 90 degrees (correct)
Q2 angle = ?
Q3 angle = ?

I need to find the directional angle for particles Q2 and Q3 - I am unsure how to find these. I was thinking I might have to draw a triangle?

Thanks,
Bensky
 
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It's an equilateral triangle.

\angle Q_1=\angle Q_2=\angle Q_3

\angle Q_1+\angle Q_2+\angle Q_3=180
 
rocomath said:
It's an equilateral triangle.

\angle Q_1=\angle Q_2=\angle Q_3

\angle Q_1+\angle Q_2+\angle Q_3=180

I'm not looking for the interior angles, I'm looking for the angle of direction of force on Q2 and Q3.
 

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