Electric Force of two hemispheres

AI Thread Summary
The discussion revolves around calculating the electric force exerted by the bottom hemisphere of a uniformly charged sphere on the top hemisphere using the Maxwell stress tensor approach. The original poster struggles with understanding tensors and seeks guidance on applying Gauss's law to find the electric field. Suggestions include integrating the force equation over the sphere, noting that the process is simpler for a hollow sphere due to the constant electric field on its surface. For a solid sphere, the integration is more complex, but symmetry allows for simplifications in calculating the radial force components. Overall, the conversation emphasizes the challenges of integrating electric fields in different geometries.
TimNguyen
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Hello.

I'm having trouble with this problem.

Suppose there is a sphere of uniform charge (Q). What is the electric force of the top hemisphere due to the bottom hemisphere?
 
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use maxwell stress tensor approach this problem
 
I apologize, I have no idea what a tensor is at all.

All I know is that the electric force equals (QE), therefore the only solution I could think of is of the form F = (1/4 Pi PermitivityConstant)(?). I'm trying to picture a way to find the electric field of the system but I just don't see it.
 
Anyone...?
 
if you are good at maths, here is one option:
use gauss laws to find equation E field at every point
integrate the F=Eq over the entire sphere
long integration, not really that hard if it is a hollow sphere. seems quite hard if it is solid, not sure

(i hope this method works)
 
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if you are good at maths, here is one option:
use gauss laws to find equation E field at every point
integrate the F=Eq over the entire sphere
long integration, not really that hard if it is a hollow sphere. seems quite hard if it is solid, not sure
forget it... the integral will go crazy...
 
for hollow sphere:

well, the e field is constant over the surface of the sphere. so all you have to do is to use a polar integration with two cosines in the function. to find the component in the away from centre direction. because by symmetry the force is outwards radially.

for solid sphere:

well, you are totally right.
 
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