Electric Force Question and Spheres

AI Thread Summary
The discussion revolves around calculating the net force acting on sphere A in a system of three identically charged spheres positioned at the corners of an equilateral triangle. The initial calculation yielded a force of 1.56 * 10^-2 N, which was deemed incorrect by a reference website. Participants suggest that the discrepancy may be due to significant figures, recommending a rounded answer of 1.6 x 10^-2 N. The method used for calculation, which involves considering the contributions of the forces from spheres B and C, is confirmed to be correct. The consensus emphasizes the importance of adhering to significant figures in scientific calculations.
delongk
Messages
18
Reaction score
0
Three identically charged spheres A, B, and C, each with a charge of +3.0 * 10-7 C, are located at the corners of a triangle whose sides are 30 cm long and all the angles are 60 deg. What is the net force acting on sphere A?

I figured the X coordinates cancel each other out. For the Y:

kqAqB/r^2 cos 30 + kqAqC/r^2 cos 30

since all charges and sides are equal:
2(kq^2/r^2) cos 30

the answer I get is 1.56 *10^-2 but the website says that is not correct. Does anyone know what I am doing wrong??
 
Physics news on Phys.org
delongk said:
Three identically charged spheres A, B, and C, each with a charge of +3.0 * 10-7 C, are located at the corners of a triangle whose sides are 30 cm long and all the angles are 60 deg. What is the net force acting on sphere A?

I figured the X coordinates cancel each other out. For the Y:

kqAqB/r^2 cos 30 + kqAqC/r^2 cos 30

since all charges and sides are equal:
2(kq^2/r^2) cos 30

the answer I get is 1.56 *10^-2 but the website says that is not correct. Does anyone know what I am doing wrong??
Perhaps it is a problem with significant figures. Try 1.6 x 10^-2. Your method is correct.

AM
 
Andrew Mason said:
Perhaps it is a problem with significant figures. Try 1.6 x 10^-2. Your method is correct.

AM
I concur with Andrew. Since they gave the charge and length with two sig figs, they probably want you to give 1.6 x10^(-2) N.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top