Electric Potential and Field Calculations for Point Charges on the x-Axis

AI Thread Summary
The discussion centers on calculating the electric potential and electric field for two point charges on the x-axis, specifically a -11.5nC charge and a +24.6nC charge separated by 14.0cm. The electric potential at the point where the electric field is zero has been determined to be 158 V. However, participants are struggling to find the two points on the x-axis where the electric potential is zero, emphasizing the need to correctly account for distances and signs in the equations. Clarifications are made regarding the use of the formulas for electric potential and electric field, highlighting the importance of considering the direction of the electric field. The conversation also touches on the necessity of accurately describing physics problems in forum titles for better assistance.
rockerdude1210
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Homework Statement



A -11.5nC point charge and a +24.6nC point charge are 14.0cm apart on the x-axis.

a) What is the electric potential at the point on the x-axis where the electric field is zero? - The answer is 1.58E2 V

b) What is the magnitude of the electric field at the two points on the x-axis where the electric potential is zero? (Input your answers in order of increasing distance from the negative point charge.)

I figured out a, but I wasn't able to get b. There should be two answers for b.


Homework Equations



E=(kQ)/r^2 - equation 1

V=(kQ)/r - equation 2



The Attempt at a Solution



I know what to do but I wasn't able to execute it. I think you have to find the value of r in equation 2 where it equals 0 and then sub that into equation 1. I'm not sure how to do this though, any help would be appreciated!
 
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V=(kQ)/r - equation 2
This is the potential for one charge only. You have two different charges.

I think you have to find the value of r in equation 2 where it equals 0 and then sub that into equation 1.
Right. That will work as soon as you get the right formula for your potential.

Keep in mind that the electric field has a direction - don't just add its magnitude, pay attention to the signs.
 
mfb said:
This is the potential for one charge only. You have two different charges.

Right. That will work as soon as you get the right formula for your potential.

Keep in mind that the electric field has a direction - don't just add its magnitude, pay attention to the signs.


Oh, sorry, I meant:

(kQ1)/r + (kQ2)/r - equation 2.

and the field for the negative charge would be towards it and the field for the positive charge would be away from it. But, I still don't know what to do with that information.
 
(kQ1)/r + (kQ2)/r - equation 2.
That is not right, the distance is different, too.

Oh, and please describe your problem in the topic. "Physics question" is pointless in a physics forum. I changed it to "Electric potential and field" and moved the thread to the right subforum.
 
Last edited:
mfb said:
That is not right, the distance is difference, too.

Oh, and please describe your problem in the topic. "Physics question" is pointless in a physics forum. I changed it to "Electric potential and field" and moved the thread to the right subforum.

What would it be then? I really can't figure it out :S

And okay
 
If you are at a position x0 and have a charge at position x1, what is the distance to the charge?
 
mfb said:
If you are at a position x0 and have a charge at position x1, what is the distance to the charge?

it would be x0 + x1
so, would that make the equation this:

(kQ1)/r + (kQ2)/ ( x0 + x1 )
 
rockerdude1210 said:
it would be x0 + x1
It is not. Just use some values to check it: is the distance between x0=3m and x1=4m the sum of both (7m)?

And don't forget the other r.
 
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