Electric Potential of charged isolated body.

AI Thread Summary
The discussion revolves around determining the electric potential of charged isolated bodies A and B after one is grounded. Initially, both bodies have zero charge and potential, but when A is charged, it creates a potential U at B. Grounding B alters the potential of A, leading to the conclusion that A's potential before grounding is V_A = U(√5 + 1)/2. The conversation emphasizes the relationship between the charge on one body and the resulting changes in potential for both bodies. The discussion highlights the importance of symmetry and potential coefficients in solving the problem.
ForTheGreater
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Homework Statement


Two equal isolated metallic bodies A & B start with no charge and zero potential. A is given a charge giving B the potential U. B is then Grounded giving A the potential U.

What potential did A have before B was grounded?

Hint: Use symmetry and use potential coefficients.

Homework Equations


V2-V1=int(E,1,2)
V=1/(4*pi*eps) * int(e_density/R dl)

The Attempt at a Solution


Don't know where to start here. The answer includes only U as variable. I think it's a question about relations.
 
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Suppose A started with charge Q, and this led to potential V at A and U at B.
If A had started with charge 2Q instead, what would the two potentials have been?
 
haruspex said:
Suppose A started with charge Q, and this led to potential V at A and U at B.
If A had started with charge 2Q instead, what would the two potentials have been?

2V and 2U.

I should have stated that with no charge both potentials is zero.

I don't see your point. The anser is V_A = U (√ 5 +1)/2
 
ForTheGreater said:
I don't see your point.
It's the first small step. Generalise it as a relationship between the charge placed on one of the objects and the consequent changes to the potentials of each object.
(Encouragingly, the answer you quote is the one I got.)
 
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