Electric potential of tiny spheres question

AI Thread Summary
The discussion revolves around calculating the electric potential energy and subsequent motion of two charged metal spheres connected by a string. The electric potential energy is determined using the formula U = kq^2/r, yielding a value of approximately 0.18225 J. For part B, the acceleration of each sphere after cutting the string can be found by applying Newton's First Law to the forces acting on them. In part C, the speed of each sphere after a long time involves using conservation of momentum and energy principles, considering the potential energy when the spheres are far apart. The conversation emphasizes the importance of applying fundamental physics concepts to solve the problem.
lodovico
Messages
17
Reaction score
0

Homework Statement


Two tiny metal spheres A and B of mass mA = 3.40 g and mB = 3.90 g have equal positive charges q = 4.50 µC. The spheres are connected by a massless nonconducting string of length d = 1.00 m, a distance that is much greater than the radii of the spheres.
(a) What is the electric potential energy of the system?
__J
(b) Suppose you cut the string. At that instant, what is the magnitude of the acceleration of each sphere?
__m/s2 (Sphere A)
__m/s2 (Sphere B)
(c) A long time after you cut the string, what is the speed of each sphere?
__m/s (Sphere A)
__m/s (Sphere B)

Homework Equations



V=U/q
V=-W/q
V=kq/r
U=kq/r^2
K=.5mv^2

The Attempt at a Solution



My teacher told me to use conservation of energy and momentum.

a) U=kq^2/r
U=((9*10^9)(4.50 µ)^2/1
U=.18225 Ji don't understand part B-C
 
Physics news on Phys.org
For b), find the force acting on both particles and use Newton's First Law to find the accelerations.

For c), use conservation of momentum and energy. What is the potential energy when the particles are very far away? How are the velocities related? ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top