Electric potential problem. Conceptual.

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An electron moving along the x-axis slows down from speed V1 to V2, indicating a potential difference between the origin and point x=2. The initial reasoning suggested that the higher potential was at x=2 due to the electron's deceleration, but the correct interpretation is that the origin is at a higher potential. This is because the electron, being negatively charged, experiences a force from an electric field directed in the negative x-direction, which correlates with a decrease in electric potential. The confusion arises from the relationship between electric field direction and potential. Understanding the behavior of negatively charged particles in electric fields clarifies the potential difference.
haydn
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Problem: An electron moving parallel to the x-axis has an initial speed of V1 at the origin. It's speed is reduced to V2 at the point x=2 (V2<V1). Calculate the potential difference between the origin and the point x=2. Which point is at the higher potential?

I was able to calculate the potential difference pretty easily but I got the second part wrong. I thought the higher potential would be at the point x=2 but the book says the origin. Here is my reasoning, please tell me where I'm going wrong:

Since the electron is decelerating along the positive x-axis, it is experiencing a force due to an electric field pointing in the -x direction. Since electric potential decreases as you move along the direction of an electric field, the origin should be at lower potential.

Thanks.
 
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Hi haydn! :smile:
haydn said:
Since the electron is decelerating along the positive x-axis, it is experiencing a force due to an electric field pointing in the -x direction. Since electric potential decreases as you move along the direction of an electric field, the origin should be at lower potential.

hmm :rolleyes: … would this be one of those negatively charged electrons? :wink:
 
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