Electrical, Circuits, Ohmslaw etc help

AI Thread Summary
To find the resistance of a copper conductor 300m long with a cross-sectional area (CSA) of 4mm², the formula R = ρl/A is used, where ρ is the resistivity (1.72 x 10^-8 Ωm), l is the length, and A is the area. The CSA must be converted from mm² to m² for accurate calculations. The resistance is directly proportional to the length and inversely proportional to the CSA. Users are encouraged to check textbooks for standard formulas and ensure they understand unit conversions. Proper application of these principles will yield the resistance value.
whybeahero
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Electrical, Circuits, Ohmslaw etc help please

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.


Homework Equations


This is all the information I have gotten from my teacher and i was wondering if anybody here can show me the formula and the answers to the questions.


The Attempt at a Solution


I would probably do something like 1.72 x 10^-8 X 200 or something i got no clue even for the other questions.
 

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You need to use the resistivity formula, should easily be able to look it up.

Make sure you use the units of the CSA correctly.
 
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Ye the thing is I have no clue on how to work that out, or what that means lol the teacher didn't explain it on how to calculate it or anything, so can you show me how to work it out please.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.

Homework Equations


This is all the information I have gotten from my teacher and i was wondering if anybody here can show me the formula and the answers to the questions.

The Attempt at a Solution


I would probably do something like 1.72 x 10^-8 X 200 or something i got no clue even for the other questions.

attachment.php?attachmentid=33099&d=1300180938.png


attachment.php?attachmentid=33100&d=1300180938.png

In the future, please post separate questions as separate threads.

For question #1: there is a formula for combining multiple resistors in series, to get the total resistance RT. Check your textbook or class lecture notes, it is a standard formula that any introductory physics textbook will have.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.
...
Has your teacher every written something like the following? Maybe it's in your textbook.

R=\frac{\,\rho\,\ell}{A}\ , where ρ is the resistivity and A is the cross-sectional area ?


.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8 Ωm.

Ohm (Ω) is the unit of resistance (R). Resistivity (ρ) is the resistance of a rod of 1 m length and 1 m2 cross section. The resistance is directly proportional to the length and inversely proportional to the cross sectional area (A).

R=ρl/A.

Calculate the resistance of that cooper wire. ρ=1.72 x 10^-8 Ωm. You have to plug in the given data, but first transform the area from mm2 to m2. Go ahead.

ehild
 
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