Electrochemical reduction of Hydrogen forms hydride?

AI Thread Summary
The discussion centers on the electrochemical reduction of hydrogen (H2) to form hydrogen anions (H-), questioning the feasibility of the reaction and the role of solvents. Participants express skepticism about finding suitable solvents, noting that many polar solvents may react with hydride ions before hydrogen can be reduced. The potential for hydride ions to reduce organic compounds similarly to metal hydrides is also explored, with the consensus that while theoretically possible, practical limitations exist. Additionally, the importance of catalysts in facilitating the reaction and the necessity for reactions to occur at the electrode surface are highlighted. Overall, the conversation emphasizes the complexities and challenges in electrochemical hydrogen reduction.
Zensation
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Would the electrochemical reduction of H2 form Hydrogen Anions of H-

H2 + 2e- -> 2H-


If this is the case, is the following true?

H- + (1/2)H2 -> H2
 
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Zensation said:
Would the electrochemical reduction of H2 form Hydrogen Anions of H-

H2 + 2e- -> 2H-

Not sure about the "electrochemical" part (I feel like you will have problems finding a solvent), but in general to get hydrides (especially ionic ones) you need to reduce hydrogen, so the reaction looks correct.

If this is the case, is the following true?

H- + (1/2)H2 -> H2

If it is intended as a full reaction, you won't be able to balance it. If it is intended as a half reaction, it is not different from the previous one.
 
Thank you. Electrochemistry is an underexplored field in my opinion with a lot of potential. Can I ask why you said there will be a problem finding a solvent? I was thinking both a H2O solution or an alcohol solution could would as long as the electrolyte is largely dissolvable and nonreactive. Based on your expertise, would you say that these Hydride anions formed via the reduction of H2 would have a similar effect on reducing organic compounds as various metal hydrides? Theoretically they should react just the same. In metal hydrides the hydride ion breaks off and reacts with the organic molecule to reduce and hydrogenate it, leaving the metal part floating in the solution, so ideally a lone hydride ion should react with the organic molecule in the same fashion, yet, with no metal byproducts.
 
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You will reduce the solvent before you will be able to reduce the hydrogen.
 
Is this so?

I remember reading that the electrical requirement to reduce H-H is not much higher than the electrical requirement to reduce a number of compounds that are very commonly reduced electrochemically, such as the bond between N-O2 bonds.

I did come across this study, in the abstract, the claim the oxidation of hydrogen only occurs when hydrogen adheres to the surface of the cathode. http://link.springer.com/chapter/10.1007/978-1-84800-936-3_3#page-1 . Though, they are speaking in terms of using a catalyst. Perhaps a catalyst would be required for the reaction to occur.
 
Zensation said:
Is this so?

I remember reading that the electrical requirement to reduce H-H is not much higher than the electrical requirement to reduce a number of compounds that are very commonly reduced electrochemically, such as the bond between N-O2 bonds.

So far you listed ethanol and water. As a rule of thumb - if something eagerly reacts with the hydride, it will react on the electrode before hydrogen gets reduced. That's redox potentials, GenChem101.

In some cases that's not exactly true, as sometimes reactions require huge overpotentials due to being kinetically hampered.

But, assuming your hydride gets produced on the electrode, to be able to react in the bulk of the solution it needs to be soluble. That means polar solvent, and these are rarely electrochemically inert.

I did come across this study, in the abstract, the claim the oxidation of hydrogen only occurs when hydrogen adheres to the surface of the cathode.

Hardly surprising, that's what happens in all electrochemical experiments - reaction takes place only on the electrode surface. Further reactions can take place in the bulk, but the only place the original reaction can go is the electrode, electrons don't freely float in the solution (with some remarkable exceptions).
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!

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