Why do the standard emf and calculated emf values differ in electrochemistry?

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The discussion centers around the relationship between cell potential (E(cell)) and the equilibrium constant (K) in electrochemistry. It begins with the equation E(cell) = E(cathode) - E(anode) and contrasts it with E(cell) = (RT/nF)ln K, leading to confusion about why these values differ. The participants clarify that E(cell) can also be expressed as E(cell) = E0red + E0ox or E(cell) = E0red - E0ox, emphasizing that the second equation is part of the Nernst equation, which accounts for concentration effects. There is a specific mention that E0 = (RT/nF)ln K applies under standard conditions where all activities are equal to one. The discussion highlights the importance of using standard redox potentials and ensuring they are referenced correctly. Ultimately, the confusion arises from mixing standard and non-standard conditions in calculating cell potential.
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If E(cell) = E(cathode)-E(anode)

and

E(cell) = (RT/nF)ln K

Then shouldn't E(cathode)-E(anode)=(RT/nF)ln k ?

I have a question asking to find the voltage of the cell and I am given a equilibrium constant... which means i should use the second equation with "k" in it, and i get the right answer. But why does this value differ from the first equation's E(cell)?

I hope this explains my question, Thx!
 
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DieCommie said:
If E(cell) = E(cathode)-E(anode)

and

E(cell) = (RT/nF)ln K

Then shouldn't E(cathode)-E(anode)=(RT/nF)ln k ?

I have a question asking to find the voltage of the cell and I am given a equilibrium constant... which means i should use the second equation with "k" in it, and i get the right answer. But why does this value differ from the first equation's E(cell)?

I hope this explains my question, Thx!

i thought E(cell) = E(anode) + E(cathode)
 
Welcome to the wonderful world of electrochemistry, perhaps the most confusing area of analytical chemistry. First off the cell potential can be expressed as:

Ecell =E0red + E0ox

or

Ecell =E0red - E0red

As to Ecell=RT/nF ln(K) This is incorrect. Think about it where are the standard redox potentials ? This is actually part of the nernst equation and used to calculate half cell effective potentials (i.e. concentration dependence).

for:

ox + ne- -> red

E=E0+RT/nF ln(K) ... K=[ox]/[red]

So then:

Ecell=Ered - Eox
 
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DrMark said:
As to Ecell=RT/nF ln(K) This is incorrect. Think about it where are the standard redox potentials ? This is actually part of the nernst equation and used to calculate half cell effective potentials (i.e. concentration dependence).
Hmm... my text explicitly says Ecell0=(RT/nF)(ln k). The description is "Relating the standard emf of the cell to the equilibrium constant". This is why i thought it should equal the emf calculated from Ered+Eox. Where are the standard redox potentials? I don't know...seems like they should be there. I suppose i understand less than i thought :confused: Thanks for trying to help though...
 
DieCommie said:
Hmm... my text explicitly says Ecell0=(RT/nF)(ln k). The description is "Relating the standard emf of the cell to the equilibrium constant". This is why i thought it should equal the emf calculated from Ered+Eox. Where are the standard redox potentials? I don't know...seems like they should be there. I suppose i understand less than i thought :confused: Thanks for trying to help though...

Sorry, some confusion here on my part. What your talking about is the standard emf, that is when all activities for products and reactants are 1. This then leads to E0=RT/nF ln(K) for a give redox reaction. The value of E0red - E0red should give the same result. Edit: Edit: Are both reduction potentials using the same reference electrode.
 
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