How Does an Electromagnetic Bell Work?

AI Thread Summary
An electromagnetic bell operates by completing a circuit when the bell push is pressed, allowing current to flow through the electromagnet. This current causes the electromagnet to attract the iron armature, which then pulls back the hammer. When the circuit is broken at point C, the current stops, releasing the hammer. Once the circuit is completed again, the springy metal resets the hammer to strike the gong. Understanding the sequence of these steps is crucial for explaining how the bell functions.
blackicerose
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I am stuck on this homework question and would apprieciate a bit of help please.

Put the following sentences in the correct order to explain how the bell works.

*The springy metal pulls back the hammer

*A current flows through the electromagnet

*At the same time, the circuit is broken at point C

*Tom presses the bell push

*The electromagnet attracts the iron armature

*At C, the circuit is complete again

*The hammer strikes the gong

Thanks in advance!
 
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Thanks

Sorry didn't read that. Thanks.

This is what I thought...

1. Tom presses the bell push.
2. At the same time, the circuit at point C is broken.
3. A current flows through the electromagnet.
4. The electromagnet attracts the iron armature.
5. At C, the circuit is complete again.
6. The springy metal pulls the hammer back.
7. The hammer strikes the gong.
 
Just imagine, if you break a part of the conducting wire in a circuit, then the current does not flow. But, if you complete the circuit by fixing the broken part, then current flows.

So you mixed up a few steps.
This site may help http://en.wikipedia.org/wiki/Electric_bell"
 
Last edited by a moderator:
does that mean i mixed up 5 & 6?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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