A piece of copper wire is formed into a single circular loop of radius 14 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.75 T in a time of 0.45 s. The wire has a resistance per unit length of 3.3 x 10-2 ohm/m. What is the average electrical energy dissipated in the resistance of the wire.(adsbygoogle = window.adsbygoogle || []).push({});

For some reason, I keep on getting the wrong answer. I'm using the formula, E=NBA/t, where B= 0.75 T, and A=0.0616 m^2. When calculating that I get 0.10 V, and then using that, I get a current of 21.65 C. Then I use, P=IV, and I get an answer of 2.16 Watts, which divided by 0.45 secods is equal to 4.8 J.

This answer is wrong, so I'm not sure where I am going wrong. Any help will be appreciated. Thanks.

**Physics Forums - The Fusion of Science and Community**

# Electromagnetic Induction Problem

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Electromagnetic Induction Problem

Loading...

**Physics Forums - The Fusion of Science and Community**