Electromagnetic shower energy spectrum

In summary, the energy of a daughter particle in an electromagnetic shower is approximated by ##E(t)=\frac{E_0}{2^t}## and the rate of change of the energy is given by ##\frac{dE}{dt}=-\frac{\ln(2)E_0}{2^t}##. The goal is to show that for small ##E##, the energy falls off like approximately ##E^{-2}##. However, simply squaring, inverting, and adding a minus sign to the initial equation is not the correct approach.
  • #1
vbrasic
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Homework Statement


The energy of a daughter particle in electromagnetic shower is approximated by, ##E(t)=\frac{E_0}{2^t}##. Show that the energy falls off like approximately ##E^{-2}##, for small ##E##.

Homework Equations


Nothing really. Just a matter of knowing how to differentiate.

The Attempt at a Solution


I have that the rate of change of the energy is given by ##\frac{dE}{dt}=-\frac{\ln(2)E_0}{2^t}##. However, I'm not sure how to approximate this by ##-E^{-2}=-\frac{2^{2t}}{E_0^2}##, which is what I think I'm supposed to be doing.
 
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  • #2
How can the energy fall off with increasing energy? Is that really the precise problem statement?
vbrasic said:
However, I'm not sure how to approximate this by ##-E^{-2}=-\frac{2^{2t}}{E_0^2}##.
That is just the initial equation squared, inverted and with a minus sign on both sides. I don't think that is the goal.
 

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