Electromagnetic Vector Fields (Static)

tazzzdo
Messages
47
Reaction score
0

Homework Statement



Use the integral form and symmetry arguments to compute the electric field produced by the following charge densities:

(i) Point charge q, placed at the origin, in 3 dimensions;
(ii) Point charge q, placed at the origin, in 2 dimensions;
(iii) Point charge q, placed at the origin, in 1 dimension;
(iv) Sphere of charge Q, with center at the origin, in 3 dimensions;
(v) Sphere of charge Q, with center at the origin, in 6 dimensions;

Homework Equations



\vec{E} and \vec{B} are the electrical and magnetic vector fields, respectively

Maxwell's Equations (with all constants set to 1):

\vec{\nabla} \times \vec{E} = -\partial\vec{B}/\partialt
\vec{\nabla} \times \vec{B} = \partial\vec{E}/\partialt + \vec{j}
\vec{\nabla} \cdot \vec{E} = \rho
\vec{\nabla} \cdot \vec{B} = 0

The Attempt at a Solution



No idea how to even set it up. I'm a Math major taking Vector Calculus, Physics is not my cup of tea lol.
 
Last edited:
Physics news on Phys.org
Gauss's law will figure heavily here. See if you can make headway with that.
 
The different dimensions are what is confusing me.
 
Think of distances in different dimensions. What is the length of a radial vector in 1,2, and 3 dimensions?
 
So that would be the vector that connects the origin to whatever point charge I'm using (in whatever dimensions the problem defines)?
 
Yes or the distance from the point charge to the field point in question.
 
Here's what I've got so far for part 4:

Vn = \frac{R}{n} \times 4R2, where n is the dimensions and R is the radius

ρ(r) = Q/(4πR3/3), where Q is the total charge of the sphere

\Rightarrow Q = \int\int\int ρ dV = ρ \times volume = (4πR3/3)ρ

So then I think I would use the integral form:

∫∫ \vec{E}(r) \cdot \hat{n} dS

But \vec{E}(r) \cdot \hat{n} = 1, right?

Then apply the divergence theorem to get (in whatever n dimensions):

\underbrace{∫...∫}_{n} (\vec{\nabla} \cdot \vec{E}) dV = \underbrace{∫...∫}_{n} ρ dV

I feel like I'm on the right track. And the approach would be the same for the point charges, except I would be using a radius r > R since the points charge is essentially the limit of the sphere charge as it approaches 0.
 
Back
Top