Sound Travel Time Calculation for Distant Listeners

AI Thread Summary
The discussion centers on calculating sound travel time for a singer's voice reaching two listeners: one 50 meters away and another 3000 kilometers away. The speed of sound at 20 degrees Celsius is approximately 343 meters per second, while radio signals travel at the speed of light, roughly 299,792 kilometers per second. The original poster initially confused the speeds of sound and light, leading to questions about the correct calculations. The formula for the speed of sound is provided as 332 + 0.6T, where T is the temperature in Celsius. Understanding these differences is crucial for accurately determining who hears the singer first and by how much time.
wikidrox
Messages
44
Reaction score
0
First here is the question:

Who will hear the voice of a singer first? A person in the balcony 50m away from the stage, or a person 3000km away at home whose ear is next to the radio? How much sooner? Assume the mic is a few cm from the singer and the temperature is 20 degrees celcius.

Now I was able to calculate how long it would take for the person 50 m away to hear it, but I don't know how to find out how long it will take for the second person to hear it. Please help me. Which equation do it use?
 
Physics news on Phys.org
The radio signal travels at the speed of light. I take it you are to assume that the singer's lips are close enough to the microphone and the hearer's ear is close enough to the radio that you can ignore those. The temperature is relevant to the speed of sound but not the speed of light.
 
Shoot! I think I did it wrong. What would the speed of sound be at 20 degrees? I just thought the speed of sound would be the same as the speed of light. I guess I was wrong.
 
wikidrox said, "I just thought the speed of sound would be the same as the speed of light."

Not quite. Light travels about a million times faster than sound!
 
Speed of Sound = 332 + 0.6T

T = temperature in degrees celsius.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top